solve the equation by expressing each side as a power of the same base and then equating exponents.
2^(7-3x)= 1/4
2^(7-3x)= 1/4
2^(7-3x) = 2^-2
so
7-3x = -2
etc
I dobt know plzzzz..
Help mek
To solve the equation 2^(7-3x) = 1/4, we can express both sides as powers of the same base, in this case, 2.
First, let's rewrite 1/4 as a power of 2. We know that 2^(-2) = 1/4.
Now, we can rewrite the equation as 2^(7-3x) = 2^(-2).
Since the bases are the same, we can equate the exponents:
7 - 3x = -2.
To solve for x, we need to isolate x by moving the constant term to the other side of the equation:
7 = -2 + 3x.
Next, we can simplify the equation:
9 = 3x.
Finally, dividing both sides by 3 gives us the solution:
x = 3.
Therefore, the solution to the equation 2^(7-3x) = 1/4 is x = 3.