how many moles of Na2C2O4 are there in 25.00 mL of a .7654 M solution of sodium oxalate?
How many moles of KMn)4 are required to reach with the moles of Na2C2O4 in the last problem?
and also,
if the KmnO4 of the last problem is in 30.30mL of solution what is the molarity (M) of the KmnO4 solution?
Number of moles =Molarity x volume in litres
The overall raction is
C2O4^2-(aq) + MnO4^-(aq) + H^+(aq) + -->
Mn^2+(aq) + CO2(g) + H2O(l)
which you need to balance to find the number of moles of KMnO4
reuse
number of moles = molarity x volume (in litres)
to find the molarity of the KMnO4 solution
To calculate the number of moles of Na2C2O4 in 25.00 mL of a 0.7654 M solution of sodium oxalate, you can use the formula:
moles = volume (in liters) x concentration (in moles per liter)
First, convert the volume of the solution from milliliters to liters:
25.00 mL = 25.00 mL x (1 L / 1000 mL) = 0.025 L
Then, use the formula to calculate the moles of Na2C2O4:
moles = 0.025 L x 0.7654 M = 0.019135 moles
Therefore, there are approximately 0.019135 moles of Na2C2O4 in 25.00 mL of the 0.7654 M solution.
Now, to calculate the number of moles of KMnO4 required to react with the moles of Na2C2O4 from the previous problem, you need to determine the stoichiometry of the reaction between Na2C2O4 and KMnO4.
The balanced chemical equation for the reaction is:
2KMnO4 + 5Na2C2O4 + 8H2SO4 → 2MnSO4 + 10CO2 + K2SO4 + 8H2O + 5Na2SO4
From the balanced equation, you can see that the stoichiometric ratio between Na2C2O4 and KMnO4 is 5:2. This means that for every 5 moles of Na2C2O4, you need 2 moles of KMnO4.
Using the moles of Na2C2O4 calculated earlier (0.019135 moles), you can calculate the moles of KMnO4:
moles of KMnO4 = (moles of Na2C2O4) x (2 moles of KMnO4 / 5 moles of Na2C2O4) = 0.007654 moles
Therefore, you would need approximately 0.007654 moles of KMnO4 to react with the moles of Na2C2O4 calculated in the previous problem.
For the final question regarding the molarity of the KMnO4 solution, you are given the volume (30.30 mL) of the solution. The molarity, denoted as M, is defined as the number of moles of a solute per liter of solution.
First, convert the volume of the solution from milliliters to liters:
30.30 mL = 30.30 mL x (1 L / 1000 mL) = 0.03030 L
Next, use the formula to calculate the molarity of the KMnO4 solution:
Molarity (M) = moles / volume (in liters)
moles = (moles of KMnO4 from the previous problem) = 0.007654 moles
Molarity (M) = 0.007654 moles / 0.03030 L = 0.2527 M
Therefore, the molarity of the KMnO4 solution is approximately 0.2527 M.