math
posted by sarah .
2i/48i
2i/48i * (4+8i)/(4+8i)
then i multiplied the top and bottom and got
8i/ 4^2 + 16i/8^2
8/80 + 16i/80
reduce to
4/5 + 2i
is this correct

math 
Reiny
You started off ok, but then ...
2i/(48i) * (4+8i)/(4+8i)
= (8i + 16i^2)/(16  64i^2)
= (8i + 16i^2)/(80)
= (i  2)/10
or
i/10  1/5
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