Find the y- and x-intercepts for the equation. Then graph the equation. Does y come first in the solution? I figured that:
the first solution is (0,-3) is this correct? and is x = to {3/7,0}? Thanks!
f(x) = - 3 - 7x
The y intercept is the value of f(x) (which we call y) when x = 0. That equals -3. The coordinates of the point are (0,-3)
The x intercept is the value of x when y = 0, which is -3/7, the coordintes of the point are (-3/7, 0)
We can't draw the graph for you. It would be straight line passing through those two points.
Thank you, so why isn't it positive {3,7,0}? Does the (0-3) come first then the (-3/7,0) OR is it opposite? Thanks
The first coordinate in a pair of numbers like (0,-3) is the x coordinate. It makes no sense to write something like {3,7,0}, as you have done. The minus sign in front of the 3/7 is because that is wnat x is when y = 0. You should see that right away by solving
0 = -3 -7x.
Thanks for helping out I see how this fits on the graph now! So my final answer will be (0,3) {-3/7,0}?
To find the y-intercept, we set x = 0 and solve for y. So, plugging in x = 0 into the equation f(x) = - 3 - 7x, we get:
f(0) = - 3 - 7(0)
f(0) = - 3
Therefore, the y-intercept is (0, -3).
To find the x-intercept, we set y = 0 and solve for x. So, plugging in y = 0 into the equation -3 - 7x = 0, we can solve for x:
-3 - 7x = 0
-7x = 3
x = 3/(-7)
x = -3/7
Therefore, the x-intercept is (-3/7, 0).
So, the first solution you provided (0, -3) is correct for the y-intercept. However, for the x-intercept, it should be (-3/7, 0), not (3/7, 0).
To graph the equation, you can plot the points (0, -3) and (-3/7, 0) on a coordinate plane and then draw a straight line passing through these points. The line should have a negative slope since the coefficient of x is -7.
So, the graph of the equation f(x) = - 3 - 7x would be a straight line passing through the points (0, -3) and (-3/7, 0).