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algebra 1

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how do you factor 16x^4 - 40x^2 + 9 I don't understand how the factoring should go. When I think of a way to factor it it doesn't turn out right.

  • algebra 1 -

    (4x^2 - 9)(2x^2 - 1)
    = (2x + 3)(2x - 3)(2x^2 - 1)

  • algebra 1 -

    16x^4 - 40x^2 + 9 = (4x^2 -9)(4x^2 -1)
    = (2x+3)(2x-3)(2x+1)(2x-1)

  • algebra 1 -

    16x^2-121

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