chemistry
posted by Viki .
Here is a following practice question on my study guide. i have no idea on how to do it. Any help would be appreciated! Thanks you.
A solution contains 26.5g NaCl in 75.0g H2O at 20 degrees Celsius. Determine if the solution is saturated, unsaturated, or supersaturated. (The solubility of NaCl at 20 Degrees is 36.0g/100g H2O) Show work.

The question is telling you that the solubility is 36 g NaCl/100 g H2O and it is asking what the solubility is in 75 g H2O. Just set up a proportion OR use dimensional analysis.
36.0 g x (75.0 g H2O)/100 g H2O) = ??
Then compare that number of ?? with 26.5 and you will know which of the it is. If you want a ratio/proportion, it would be set up like this:
36/100 = ??/75 
Thank you!
But how would i figure out the "??"
I totally suck at chemistry!.. idk how to find the solubility ..? 
There is no chemistry in the problem. It's all math and not very advanced math at that.
How do you figure out the ?? in the equation:
36.0 x (75.0 g H2O/100 g H2O) = ??
You key in 36.0 on your calculator, multiply by 75.0 and divide by 100. That's all there is to it.