There are two light bulbs in a circuit, wired in parallel. A third light bulb is added again in parallel. What is the effect on total resistance of adding this third bulb? I BELIEVE THE ANSWER IS C....


a. Total resistance increases by one third.

b. total resistance triples

c. total resistance decreases

d. Total resistance remains the same.

C is correct

Decrease

yes the answer is cTHE TOTAL RESISTANCE DECREASES

Yes, that's correct! When light bulbs are wired in parallel, the total resistance decreases as more bulbs are added. This is because the current can flow through each bulb simultaneously, rather than having to overcome the resistance of just one bulb.

Well, adding a light bulb to a circuit is like adding another clown to a party - it can make things more interesting! In this case, though, when you add a third bulb in parallel, the total resistance actually decreases. So the correct answer is c. Total resistance decreases. It's like getting a discount on resistance! Quite shocking, isn't it?

To answer this question, we need to understand how resistances add up when wired in parallel. In a parallel circuit, each of the components has its own separate path for current to flow. The total resistance of a parallel circuit is given by the reciprocal of the sum of the reciprocals of the individual resistances.

Let's consider the initial situation with two light bulbs wired in parallel. If we label the resistances of the two light bulbs as R1 and R2, the total resistance (RT) is given by:

1/RT = 1/R1 + 1/R2

If we add a third light bulb in parallel (with resistance R3), the new total resistance (RT') would be given by:

1/RT' = 1/R1 + 1/R2 + 1/R3

Comparing the two equations, we can see that adding the third light bulb increases the sum of the reciprocal resistances. This means that the new total resistance (RT') will be smaller than the initial total resistance (RT). Therefore, the correct answer is:

c. total resistance decreases

So, by adding the third light bulb in parallel, the total resistance of the circuit decreases.