Solve the problem. The volume V of a gas varies inversely as the pressure P on it. The volume of a gas is 240 cm3 under a pressure of 23 kg/cm2 What will be its volume under a pressure of 30 kg/cm2?

In this situation, because of the inverse proportionality,

P1/P2 = V2/V1
1 and 2 denote the two different conditions.
23/30 = V2/240

Solve for V2, the volume at P2 = 30

aaaahhhh, now i get it

however, the options are:

184, 166, 313, or 297

I got 313, is this correct?

(240*30)/23=313

No, it is 184. You incorrectly rearranged the equation I wrote.

The volume has to decrease when you increase the pressure.

To solve this problem, we can use the concept of inverse variation. Inverse variation means that as one variable increases, the other variable decreases, and vice versa. In mathematical terms, inverse variation can be represented as:

V ∝ 1/P

Where V is the volume and P is the pressure.

The formula for inverse variation can be rewritten as:

V = k/P

Where k is a constant.

To find the value of k, we can use the given information. The volume of the gas is 240 cm^3 when the pressure is 23 kg/cm^2.

240 = k/23

To solve for k, we can multiply both sides of the equation by 23:

k = 240 * 23

k = 5520

Now that we have the value of k, we can find the volume of the gas under a pressure of 30 kg/cm^2.

V = 5520/30

V ≈ 184 cm^3

Therefore, the volume of the gas under a pressure of 30 kg/cm^2 is approximately 184 cm^3.