Post a New Question


posted by .

solve each identity algebraically



  • math -

    my usual approach is to start with the "messy" side, and change everything to sines and cosines.

    =(1- sinx/cosx)/(1 - cosx/sinx)
    = (cosx-sinx)/cosx * (sinx)/ (sinx - cosx)
    = (-1)sinx/cosx
    = -tanx

    perform similar steps for the second one, bet you'll get it

  • math -

    I got (1- sinx/cosx)/(1 - cosx/sinx)
    but how did (1- sinx/cosx) turn to (cosx-sinx)/cosx?

  • math -

    nevermind, found out :) thanks

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question