What volume (in liters) does 3 g sample of Argon (Ar) gas occupy at standard conditions (STP)?
To determine the volume of a given sample of gas at standard conditions (STP), we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)
At standard conditions, the pressure (P) is equal to 1 atmosphere (atm) and the temperature (T) is equal to 273.15 Kelvin (K).
First, we need to calculate the number of moles (n) of Argon gas using its molar mass.
The atomic mass of Argon (Ar) is approximately 39.95 g/mol.
Given that you have a 3 g sample of Argon gas, we can calculate the number of moles as follows:
n = mass / molar mass
n = 3 g / 39.95 g/mol
n ≈ 0.0751 mol
Now that we have the number of moles, we can rearrange the ideal gas law equation to solve for the volume (V):
V = nRT / P
Substituting the values into the equation:
V = (0.0751 mol)(0.0821 L.atm/mol.K)(273.15 K) / 1 atm
V ≈ 1.92 L
Therefore, the 3 g sample of Argon gas at standard conditions (STP) occupies approximately 1.92 liters.