math
posted by Jeff .
If y = u+ 2e^u and u = 1+lnx, find dy/dx when x= (1/e) ?

When x = 1/e, u = 0 and y = u + 2e^u = 2
dy/dx = (dy/du)*(du/dx) = (1 + 2e^u)(1/x)
= 3*e = 3e
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