What is the theoretical yield of calcium carbonate if 2.97 grams of calcium chloride dihydrate reacts with excess sodium carbonate according to the balanced chemical reaction shown below?
CaCl2•2H20(aq)+Na2CO3(aq)->CaCO3(aq)+2NaCL(aq)+2H20(I)
Please use molar mass values calculated and rounded to the hundredths place, and round your answer to the hundredths place.
to find the molar mass, i did:
Ca = 40.08
Cl2 = (35.45) x 2 = 70.9
2H2O = (18.02) x 2 = 36.04
40.08 + 70.90 + 36.04 = 147.02 g/mol
To find the theoretical yield, i did:
2.97g CaCl•2H2O x (1 mol CaCl•2H2O/147.02g CaCl•2H2O) x (1 mol CaCO3/1 mol CaCl•2H2O) x (100.09/1 mol CaCO3) = 2.04 g
Did I do the theoretical yield equation correctly?
Yes, your procedure is correct. I obtained 147.014 for CaCl2.2H2O and 100.087 for CaCO3 but I'm using a calculator on the internet and that may not agree with the numbers on your periodic table. They should agree if both contain the most up to date information. Using my numbr I obtained 2.0219 g for the theoretical yield, which rounds to 2.02. Here is the site I use for molar mass calculations if you wish to compare their numbers versus your numbers. http://environmentalchemistry.com/yogi/reference/molar.html
Yes, you did the theoretical yield equation correctly.
To calculate the theoretical yield, you need to use the molar mass values as you have done.
First, determine the molar mass of CaCl2•2H2O:
Ca: 1 x 40.08 = 40.08 g/mol
Cl2: 2 x 35.45 = 70.90 g/mol
2H2O: 2 x 18.02 = 36.04 g/mol
Add the molar masses together to get the molar mass of CaCl2•2H2O:
40.08 + 70.90 + 36.04 = 147.02 g/mol
Next, multiply the given mass of CaCl2•2H2O (2.97 g) by the following conversion factors to get the theoretical yield in grams of CaCO3:
2.97 g CaCl2•2H2O x (1 mol CaCl2•2H2O/147.02 g CaCl2•2H2O) x (1 mol CaCO3/1 mol CaCl2•2H2O) x (100.09 g CaCO3/1 mol CaCO3) = 2.04 g CaCO3
Therefore, the theoretical yield of calcium carbonate is 2.04 grams.
Yes, you have correctly calculated the molar mass of calcium chloride dihydrate as 147.02 g/mol.
To find the theoretical yield of calcium carbonate, you need to use stoichiometry and convert grams of calcium chloride dihydrate to moles of calcium chloride dihydrate, and then moles of calcium chloride dihydrate to moles of calcium carbonate, and finally moles of calcium carbonate to grams of calcium carbonate.
Your calculation is correct:
2.97 g CaCl2•2H2O x (1 mol CaCl2•2H2O/147.02g CaCl2•2H2O) x (1 mol CaCO3/1 mol CaCl2•2H2O) x (100.09/1 mol CaCO3) = 2.04 g
Therefore, the theoretical yield of calcium carbonate is 2.04 grams.