Sin(X-y)sin(x+y)=sin^2 x - sin^2 y
work on one side only...so i worked on the right
=(sinx-siny)(sinx+siny) does that equal
sin(x-y)sin(x+y)??? help!
Duplicate post; already answered.
Refer to your previous post.
To determine if (sinx-siny)(sinx+siny) is equal to sin(x-y)sin(x+y), you can use the identity for the difference of squares, which states that (a-b)(a+b) is equal to a^2 - b^2.
Using this identity, let's apply it to (sinx-siny)(sinx+siny):
= (sinx)^2 - (siny)^2
Now, let's compare this expression to the right side of the given equation:
sin^2 x - sin^2 y
We can see that the expressions are indeed equal.
Therefore, (sinx-siny)(sinx+siny) is equal to sin(x-y)sin(x+y).