A flag of mass 2.2 kg is supported by a single rope as shown in the figure below. A strong horizontal wind exerts a force of 10 N on the flag. Find the tension in the rope and the angle θ the rope makes with the horizontal.

Tension = N
θ = °

We will be glad to critique your work. I realize that you cannot provide the "figure below", but you could have made a better effort to describe it.

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To solve this problem, we can use Newton's second law, which states that the sum of all the forces acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the flag is not accelerating, the sum of the forces in the vertical direction must be equal to zero.

Let's break down the forces acting on the flag:

1. The force of gravity: The flag has a mass of 2.2 kg, so the force of gravity acting on it can be calculated using the formula F = m * g, where g is the acceleration due to gravity (approximately 9.8 m/s^2). Therefore, the force of gravity is F_gravity = 2.2 kg * 9.8 m/s^2.

2. The tension in the rope: The tension in the rope provides an upward force to balance the force of gravity and the horizontal wind force. Let's call this tension T.

3. The horizontal wind force: The wind exerts a force of 10 N on the flag in the horizontal direction.

To find the tension in the rope, we need to consider the forces in the vertical direction:

F_gravity - T * cos(θ) = 0

Simplifying the equation, we have:

T * cos(θ) = F_gravity

Plugging in the values, we have:

T * cos(θ) = 2.2 kg * 9.8 m/s^2

To find the value of T, we need to know the value of θ. The angle can be found using the horizontal wind force:

T * sin(θ) = 10 N

Dividing the two equations, we get:

(T * sin(θ)) / (T * cos(θ)) = 10 N / (2.2 kg * 9.8 m/s^2)

Simplifying the equation, we have:

tan(θ) = 10 N / (2.2 kg * 9.8 m/s^2)

Taking the inverse tangent (tan^-1) of both sides, we get:

θ = tan^-1(10 N / (2.2 kg * 9.8 m/s^2))

Using a calculator, we can find the value of θ.