x+6=24
x+6+(-6)=24 +(-6)
x= 18 is this right.
3(x+4)=5(x-2)
3x+12=5x-10
3x-5x=12-10
2x=-22
x=-11 is this problem right
This first one is right. The second one, I think you did your math wrong
3x-5x=-10-12
-2x=-22
x=11
3x-5x gives you -2x not 2x and on 12-10 does not give you 22
your suppose to subtract 12 from both sides
Let's go through each problem step by step to check if the answers are correct.
For the first problem:
Given: x + 6 = 24
To isolate x, we need to eliminate the 6 from the left side of the equation. We can do this by subtracting 6 from both sides of the equation:
x + 6 - 6 = 24 - 6
x = 18
So, your answer for the first problem, x = 18, is correct.
For the second problem:
Given: 3(x + 4) = 5(x - 2)
To solve this equation, we will distribute the 3 and 5 to the terms inside the parentheses:
3x + 12 = 5x - 10
Next, we want to isolate the variable x. We can do this by moving the terms with x to one side of the equation and the constant terms to the other side:
3x - 5x = -10 - 12
-2x = -22
To solve for x, we need to divide both sides of the equation by -2:
-2x / -2 = -22 / -2
x = 11
So, it looks like there was a mistake in your calculation for the second problem. The correct answer is x = 11, not x = -11.
I hope this helps clarify the solutions for both problems!