posted by Dan .
Use the functions f(x)=1/8x-3 and
g(x)=x^3 to find the indicated value or function.
(g^-1 X f^-1)(-3)
f^-1)(-3) is the value of x that you get when f(x) = -3. That value is 0.
g^-1(0) is the value of x that you get when g(x) = 0. That is also zero.
So (g^-1*f^-1)(-3) = 0
In functional form,
f^-1(x) = 8(x+3)
g^-1(x) = x^(1/3)
(g^-1*f^-1)(x) = [8(x+3)]^1/3