# calculus

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evaluate: integration of x^2 (square root of (1-2x^3))dx

• calculus -

Let u = 1-2x^3
du = =6 x^2 dx
= -(1/6)*u^(3/2)/(3/2)
= -(1/9)(1-2x^3)^(3/2)

Check my math

• calculus -

thanks

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