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algebra

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4-3/4b^5c^3 / -4/6b^2c^-3 =

four minus three fourths b to the 5th power c to the third power divided by negative four sixths b to the second power and c to the negative 2 power

  • algebra -

    the way you typed it , and the way you stated it,
    I would multiply top and bottom by 12 to get rid of the fractions.

    (48 - 9b5c3)/(-8b2c-3) or perhaps
    (48c3 - 9b5c6)/-8b2

    other than that I see little else that I would do

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