algebra
posted by Lisa .
43/4b^5c^3 / 4/6b^2c^3 =
four minus three fourths b to the 5th power c to the third power divided by negative four sixths b to the second power and c to the negative 2 power

the way you typed it , and the way you stated it,
I would multiply top and bottom by 12 to get rid of the fractions.
(48  9b^{5}c^{3})/(8b^{2}c^{3}) or perhaps
(48c^{3}  9b^{5}c^{6})/8b^{2}
other than that I see little else that I would do
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