a 50.0g silver spoon at 20.0c is placed in a cup of coffee at 90.0c. How much heat does the spoon absorb from the coffee to reach a temperature of 89.0c
assistance needed
To calculate the heat absorbed by the silver spoon, we can use the equation:
q = m * c * ΔT
Where:
q is the heat absorbed (in Joules)
m is the mass of the spoon (in grams)
c is the specific heat capacity of silver (0.235 J/g°C)
ΔT is the change in temperature (in °C)
First, let's calculate the change in temperature of the spoon:
ΔT = 89.0°C - 20.0°C
ΔT = 69.0°C
Now, let's calculate the heat absorbed by the spoon:
q = 50.0g * 0.235 J/g°C * 69.0°C
q = 810.75 J
Therefore, the spoon absorbs 810.75 Joules of heat from the coffee.
To calculate the heat absorbed by the spoon, we can use the formula:
Q = mcΔT
Where:
Q is the heat absorbed or released (in joules)
m is the mass of the object (in grams)
c is the specific heat capacity of the material (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
In this case, we need to calculate the heat absorbed by the spoon, so the mass of the spoon (m) is 50.0g, the specific heat capacity of silver (c) is 0.235 J/g°C (joules per gram per degree Celsius), and the change in temperature (ΔT) is -1.0°C (since the spoon goes from 90.0°C to 89.0°C).
First, let's calculate the heat absorbed:
Q = (50.0g) * (0.235 J/g°C) * (-1.0°C)
Q = -11.75 J
The heat absorbed by the spoon is -11.75 joules. The negative sign indicates that the spoon is losing heat to the coffee.