please help me by showing steps
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Assuming atmospheric pressure to be 1.01 * 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0m below the surface of the ocean?
thanks again:)
It is
Po + (sea water density)x g x(depth)
The units will be Pascals if density is in kg/m^3 and depth is in meters.
Po is the atmospheric pressure. g is the acceleration of gravity, 9.81 m/s^2
You should get about 2.52*10^5 Pa for your answer
thanks
To find the absolute pressure at a certain depth below the surface of the ocean, you can use the formula:
P = P0 + ρgh
Where:
P is the absolute pressure at the given depth
P0 is the atmospheric pressure at the surface (1.01 * 10^5 Pa in this case)
ρ is the density of the fluid (sea water in this case, with a density of 1025 kg/m^3)
g is the acceleration due to gravity (approximated to 9.8 m/s^2)
h is the depth below the surface of the fluid (15.0 m in this case).
Now, let's substitute the values into the formula:
P = (1.01 * 10^5 Pa) + (1025 kg/m^3) * (9.8 m/s^2) * (15.0 m)
Calculating this equation will give us the absolute pressure at a depth of 15.0 m below the surface of the ocean.