A student placed 10.5g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.- mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 20.0-mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100mL. of the final solution?

Question

A student placed 10.5g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.- mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 20.0-mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100mL. of the final solution?

answer in Grams

Answer 1

duplicate post. Answered the original.

Answer 2

To find the number of grams of glucose in 100mL of the final solution, we need to determine the concentration of glucose in the solution and then use that concentration to calculate the mass.

First, let's calculate the concentration of glucose in the 20.0mL sample that was diluted to 0.500L. We know that the volume of the diluted solution is 0.500L, and the concentration is the amount of solute (glucose) divided by the volume.

We can use the formula:

Concentration (C1) = (initial volume x initial concentration) / final volume

Let's substitute the values:

C1 = (20.0 mL x initial concentration) / 0.500 L

Next, we can rearrange the formula to solve for the initial concentration:

Initial concentration = (C1 x final volume) / initial volume

Given that C1 is the concentration of the diluted solution, which would be the concentration of the final solution, and we calculated it to be 0.500 L, the final volume is 0.500 L, and the initial volume is 20.0 mL, we can substitute these into the formula:

Initial concentration = (0.500 L x 0.500 L) / 20.0 mL

Now, we know that 1 mL is equal to 1 gram, so we can convert the initial concentration from mL/L to g/L:

Initial concentration (g/L) = (0.500 L x 0.500 L) / 20.0 mL

Initial concentration (g/L) = 25.0 g/L

Since we diluted the 20.0 mL sample to 0.500 L, the concentration of glucose in the final solution is also 25.0 g/L.

Finally, to find the number of grams of glucose in 100 mL of the final solution, we can use the formula:

Mass of glucose (g) = (concentration x volume) / 1000

Mass of glucose = (25.0 g/L x 100 mL) / 1000

Mass of glucose = 2.50 g

Therefore, there are 2.50 grams of glucose in 100 mL of the final solution.