please help
There are six books in a stack, and each book weighs 5 N. The coefficient of static friction between the books is 0.2. With what horizontal force must one push to start sliding the top five books off the bottom one?
please walk me through this
thanks alot:D
To determine the horizontal force required to start sliding the top five books off the bottom one, we need to consider the static friction between the books.
The static friction force can be calculated using the formula:
Fs = μs * N
where Fs is the static friction force, μs is the coefficient of static friction, and N is the normal force.
In this case, the normal force is the weight of the six books combined since they are stacked on top of each other. The weight of one book is given as 5 N, so the total weight of the books is:
Weight = 5 N/book * 6 books
Weight = 30 N
Therefore, the normal force N is 30 N.
Now, let's calculate the static friction force:
Fs = 0.2 * 30 N
Fs = 6 N
The static friction force between the books is 6 N.
To start sliding the top five books off the bottom one, we need to apply a horizontal force greater than the static friction force. Since the top five books are being pushed as a unit, the force required to slide them equals the static friction force of 6 N.
Therefore, to start sliding the top five books off the bottom one, you need to apply a horizontal force of at least 6 N.
force friction between books= mu*mg
= .2*5*5=2.5N