# algebra 2 honors

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how do you solve problems like :
log3x-log5=1

• algebra 2 honors -

log3x-log5=1
log (3x/5) = 1
then 3x/5 = 10^1

3x = 50
x = 50/3

check:
log(3(50/3)) - log5
= log50-log5
= 1.69897 - .69897
= 1

• algebra 2 honors -

how do u solve
(6/4x^2)+ (2/5x)

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