hi can someone please help me with this question.
The SST Concorde flies at a speed of Mach 1.5. What is the half-angle of the conical shock wave formed by the Concorde at this speed?
http://hypertextbook.com/physics/waves/shock/
im still confused
Read the link. You could not have read it in one minute. IT gives the sine of the total angle, solve for that, and take half of it.
Certainly! I can help you with that.
To find the half-angle of the conical shock wave formed by the Concorde at a speed of Mach 1.5, we can use the equation for the half-angle of a conical shock wave:
sin(theta) = 1 / Mach number
In this case, the Mach number is 1.5. Substituting this value into the equation, we get:
sin(theta) = 1 / 1.5
To find the value of theta, we can take the inverse sine (also known as arcsine) of both sides of the equation. This will give us the value of theta in radians. If you prefer the angle in degrees, you can convert radians to degrees using the formula: degrees = radians * (180 / pi). Let's calculate.
sin(theta) = 1 / 1.5
theta = arcsin(1 / 1.5)
Using a scientific calculator or an online tool, we find:
theta ≈ 41.8 degrees
So, the half-angle of the conical shock wave formed by the Concorde at a speed of Mach 1.5 is approximately 41.8 degrees.