A weight suspended from a spring is seen to bob up and down over a distance of 37 cm twice each second.

What is frequency in units of Hz?
What is the period in units of s.?
What is the amplitude in units of cm?

"twice each second" means the same thing as 2 per second or 2 Hz.

1 divided by the frequency is the period. If there are two vibration periods in 1 second, how long does it take to have one vibration?

37 cm is twice the amplitude

Well, if the weight is bobbing up and down twice each second, that means it is completing two cycles in one second. So the frequency would be 2 Hz. Think of it like this: you could call it the "spring fling" with a frequency of 2 "spring flings" per second.

Now, to find the period, we just need to flip the frequency upside down. So the period would be 1/2 seconds, or 0.5 s. It's like saying the weight takes a half-second nap between each "spring fling".

Finally, the amplitude is simply the distance the weight travels from its equilibrium position, which is 37 cm in this case. So the amplitude is 37 cm. It's like the weight saying, "I'm going to stretch spring and reach as far as I can, 37 cm."

Hope that puts a "spring" in your step!

To solve this problem, let's define the given information.

Amplitude (A) = 37 cm
Frequency (f) = ? (in Hz)
Period (T) = ? (in s)

The frequency (f) is the number of complete oscillations (or cycles) per unit time, measured in Hz (Hertz).

To find the frequency, we need to find the number of cycles per second. In this case, the weight bobbed up and down twice each second, so the frequency is 2 cycles/second or 2 Hz.

Therefore, the frequency is 2 Hz.

The period (T) is the time taken for one complete oscillation, measured in seconds (s).

To find the period, we can use the formula T = 1/f, where f is the frequency.

In this case, the frequency is 2 Hz, so the period is T = 1/2, which equals 0.5 seconds.

Therefore, the period is 0.5 s.

The amplitude (A) is the maximum displacement from the equilibrium position, measured in centimeters (cm).

In this case, the amplitude is given as 37 cm.

Therefore, the amplitude is 37 cm.

To answer these questions, we need to understand the concepts of frequency, period, and amplitude in the context of a vibrating system like a weight suspended from a spring.

Frequency (f) is the number of complete cycles or oscillations that occur per unit of time. It is measured in units of Hertz (Hz), where 1 Hz is equal to one cycle or oscillation per second.

Period (T) is the time taken for one complete cycle or oscillation. It is the reciprocal of frequency and is measured in units of seconds (s).

Amplitude (A) is the maximum displacement of the weight from its equilibrium position. It represents the maximum distance the weight moves from the center of its oscillation in either direction. It is typically measured in units of length, such as centimeters (cm).

In the given question, we are told that the weight suspended from the spring bobs up and down over a distance of 37 cm twice each second. This means that the weight completes 2 complete cycles or oscillations in 1 second.

To find the frequency:

Frequency (f) = Number of cycles / Time

In this case, the number of cycles is 2 and the time is 1 second.

Frequency (f) = 2 cycles / 1 second = 2 Hz

Therefore, the frequency is 2 Hz.

To find the period:

Period (T) = 1 / Frequency (f)

In this case, the frequency is 2 Hz.

Period (T) = 1 / 2 Hz = 0.5 s

Therefore, the period is 0.5 s.

To find the amplitude:

Since the weight is seen to bob up and down over a distance of 37 cm, the amplitude is 37 cm.

Therefore, the amplitude is 37 cm.