how do you put these in y=mx+b form
3x+5y=8
16-5x=2y
Are you supposed to use the elimination or substution method?
yes to change it to y=mx+b form
Yep, I would choose substition it is so much easier let me do a quickk browse of my book to refresh and ill help.
okay thanks
To put an equation in the form y = mx + b, where m is the slope and b is the y-intercept, follow these steps:
1. Start with the given equation.
2. Isolate the term with y on one side of the equation by subtracting or adding the other terms on both sides.
Let's apply this method to the given equations:
1. For the equation 3x + 5y = 8:
To isolate the term with y, subtract 3x from both sides:
5y = -3x + 8
Now, divide all terms by 5 to solve for y:
y = (-3/5)x + 8/5
Hence, the equation is in y = mx + b form, where m = -3/5 and b = 8/5.
2. For the equation 16 - 5x = 2y:
To isolate the term with y, divide both sides by 2:
(16 - 5x) / 2 = y
Simplify the expression:
8 - (5/2)x = y
Rearrange:
y = -(5/2)x + 8
Now, the equation is in y = mx + b form, where m = -(5/2) and b = 8.
Therefore, the equations 3x + 5y = 8 and 16 - 5x = 2y can be written in y = mx + b form as y = (-3/5)x + 8/5 and y = -(5/2)x + 8, respectively.