Algebra 2
posted by Bill .
Okay I have :
a ball is thrown with an initial velocity of 40 ft/second from a height of 4 feet. h(t)=16t+40t+4
a) what is the highest point reached by the ball?
b) at what time will the ball reach the highest point?

your formula is wrong.
h(t)=16t^2 + 40t+4
v(t)=4016t
so max height is when v(t)=0 or t=40/16
and the max height is found by plugging that into the height equation. 
5 seconds
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