I know how to balance equations, but for some reason I can't seem to get this problem. Can anyone help?

FeO3 + CO to Fe2S3 + NH4Br

Thats weird. I just learned this today, but on side has sulfur and the other side does not.

wow, I just copied down two problems, heres the actual equation:

FeBr3 + (NH4)2S to Fe2S3 + NH4Br

I think its

2FeBr3 + 3(NH4)2S --->> Fe2S3 + 6NH4BR

that is it, thank you very much

Certainly! I'd be happy to help you balance this equation. Balancing chemical equations involves ensuring that the number of atoms of each element is the same on both sides of the equation.

Let's start by counting the number of atoms for each element on both sides of the equation:

On the left side:
Fe: 1
O: 3
C: 1
O: 1

On the right side:
Fe: 2
S: 3
N: 1
H: 4
Br: 1

To balance this equation, we need to adjust the coefficients (the numbers in front of the chemical formulas) to ensure that the number of atoms of each element is the same on both sides.

Let's start by balancing the iron (Fe) atoms. Currently, there is 1 Fe atom on the left side and 2 Fe atoms on the right side. To balance this, we can put a coefficient of 2 in front of FeO3 on the left side:

2 FeO3 + CO to Fe2S3 + NH4Br

Now, we have:
Fe: 2
O: 6
C: 1
O: 1

On the right side:
Fe: 2
S: 3
N: 1
H: 4
Br: 1

Next, let's balance the sulfur (S) atoms. Currently, there are 3 S atoms on the right side and none on the left side. To balance this, we can put a coefficient of 3 in front of Fe2S3 on the right side:

2 FeO3 + CO to 3 Fe2S3 + NH4Br

Now, we have:
Fe: 2
O: 6
C: 1
O: 1

On the right side:
Fe: 6
S: 9
N: 1
H: 4
Br: 1

Next, let's balance the nitrogen (N) atoms. Currently, there is 1 N atom on the right side and none on the left side. To balance this, we can put a coefficient of 2 in front of NH4Br on the right side:

2 FeO3 + CO to 3 Fe2S3 + 2 NH4Br

Now, we have:
Fe: 2
O: 6
C: 1
O: 1

On the right side:
Fe: 6
S: 9
N: 2
H: 8
Br: 2

Finally, let's balance the hydrogen (H) and bromine (Br) atoms. Currently, there are 8 H atoms and 2 Br atoms on the right side, but none on the left side. To balance this, we can put a coefficient of 8 in front of NH4Br on the right side:

2 FeO3 + CO to 3 Fe2S3 + 2 NH4Br

Now, we have:
Fe: 2
O: 6
C: 1
O: 1

On the right side:
Fe: 6
S: 9
N: 2
H: 16
Br: 4

Now, all the elements are balanced on both sides of the equation. The balanced equation is:

2 FeO3 + CO to 3 Fe2S3 + 2 NH4Br

I hope this explanation helps you understand how to balance chemical equations!