The equation of the function is: f(x)=4-2(x-6)^1/3, for x not equal to 5 calculate precisely the value of f(x). so I got this: 5=4-2(x-6)^1/3 1=-2(x-6)^1/3 (-1/2)=(x-6)^1/3 (-1/2)^3=(x-6) -.125=x-6 now the next step is suposed to be …
Problem:: A 4.80 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.5 N at an angle q= 17.5° above the horizontal. What is the speed of the block 3.90 seconds after it starts moving?
A particle is moving around the unit circle (the circle of radius 1 centered at the origin). At the point (.6, .8) the particle has horizontal velocity dx/dt=3. what is its vertical velocity dy/dt at that point?
13.875-0.1875(56.375)/8-2 (1/8+27.125/300.875 the answer is 1.1908 but when i calculate use calculator i cant get the answer.we need solve value in the bracket first then multipe by first value or how ?