A 5.0 kg bucket of water is raised form a well by a rope. If the upward acceleratiopn of the bucket is 3.0 m/s^2 find the force exerted by the rope on the bucket of water
what exactly do i do here?
3.0 m/s^2 upward? is this the Fn? I have no idea how to do this problem...
odd i never seen this formula before and we haven't goten to tension yet thank you
The net force acting on the bucket is
Fn = T - Mg = M a
T is the tension in the rope.
T = M (g + a) = 12.8 m/s^2 * 5.0 kg = ?
The formula I used is Newton's second law. You probably have heard about that. Tension is one of the two forces acting on the bucket. The other is the weight force, W = M a
To solve this problem, you need to apply Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). In this case, the net force is the force exerted by the rope on the bucket of water.
First, let's define the variables:
m = mass of the bucket of water = 5.0 kg
a = acceleration = 3.0 m/s^2 (upward)
Next, plug the given values into the equation F_net = m * a to find the net force:
F_net = m * a
F_net = 5.0 kg * 3.0 m/s^2
F_net = 15.0 N
So, the force exerted by the rope on the bucket of water is 15.0 Newtons (N) directed upward.
To summarize the steps:
1. Identify the variables given in the problem.
2. Use Newton's second law (F_net = m * a) to calculate the net force.
3. Substitute the given values into the equation and perform the necessary calculations.
4. The result will be the force exerted by the rope on the bucket of water.