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Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees.

360 degrees - 45=315 degrees.
Is this right?

  • Pre-calculus -

    x = arcsin (√2/2)

    since √2/2 is positive and the sine of an angle is positive in the I and II quadrant
    x = 45 degrees or 135 degrees.

    sin 315 = - √2/2

  • Pre-calculus -

    Not quite. The angles that satisfy that equation are 45 and 135 degrees. the sine of 315 degrees is -sqrt2/2

    The Sine function is positive in the first and second quadrants

  • Pre-calculus -


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