alg 2+urgent please.

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2/the 6th root of 81

the answer gave an answer of "2 3rd root of 3/3"

sorry i didn't type the root signs, i dunno how.
can you show me how to work this?

  • alg 2+urgent please. -

    the book gave me that answer.

  • alg 2+urgent please. -

    2/the 6th root of 81
    = 2/[(3^4)^(1/6)]
    = 2/3^(2/3)
    now multiply top and bottom by 3^(1/3)
    which would give you 3^(3/3) or 3 in the bottom

    = 2(3^(1/3))/3
    = 2*cuberoot(3)/3, your answer.

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