Can anyone help me on these two problems also. I am getting so confused and tired.
The length of a rectangle is fixed at 27cm. What lengths will make the perimeter greater than 100cm?
also this problem
Trians A and B are traveling in the same direction on parellel tracks. Trian A is traveling at 40 miles per hour and train B is traveling at 50 miles per hour. Train A passes a station at 7:15am. If train B passes the same station at 7:45am, at what time will train B catch up to train A?
When will train B catch up with train A?
The first: doesn't make sense. I will assume you are looking for widths.
P=2Length +2width
100<=2(27)+2*W
solve for w.
Thank you for your help, it is width.
So i take the 2and times it by the 27.
With that answer figure out the difference between the 2 times 27 and minus from 100 then divid by 2. Is this the way to figure out the problem?
Sure, I can help you with those problems! Let's break them down step by step.
1) Finding the lengths that will make the perimeter of a rectangle greater than 100cm:
To solve this problem, we need to understand the formula for calculating the perimeter of a rectangle. The perimeter is given by the equation: P = 2L + 2W, where L is the length of the rectangle and W is the width.
In this case, the length is fixed at 27cm. So the formula becomes: P = 2(27) + 2W, or P = 54 + 2W.
Now, we want to find the values of W that will make the perimeter greater than 100cm. We can set up an inequality to represent this:
54 + 2W > 100
To solve this inequality, we subtract 54 from both sides:
2W > 100 - 54
2W > 46
Finally, we divide both sides by 2 to isolate W:
W > 23
So, any length greater than 23cm will make the perimeter of the rectangle greater than 100cm.
2) Finding the time when Train B catches up with Train A:
To solve this problem, we can first determine the time difference between when Train A passes the station and when Train B passes the station. Since Train B passes the station 30 minutes (0.5 hours) after Train A, we can consider this time as the head start for Train A.
Now, we can calculate the distance traveled by both trains during this time. The distance can be given by the equation: Distance = Speed × Time.
Train A has a speed of 40 mph and a head start of 0.5 hours, so its distance traveled would be: DistanceA = 40 × 0.5 = 20 miles.
Now, let's assume that Train B is catching up to Train A at a certain speed. The relative speed between the two trains is the difference in their speeds, which is: Relative Speed = SpeedB - SpeedA = 50 - 40 = 10 mph.
Since Train B needs to cover the head start distance of 20 miles, we can now calculate the time it takes for Train B to catch up to Train A. Using the equation Distance = Speed × Time, we have:
20 = 10 × Time
Time = 20/10
Time = 2 hours
Therefore, Train B will catch up to Train A at 2 hours after Train A passed the station. If Train A passed the station at 7:15am, then Train B will catch up at 9:15am.
I hope that helps! Let me know if you have any further questions.