Post a New Question

chemistry

posted by .

Benzene has a heat of vaporization of 30.72kj/mol and a normal boiling point of 80.1 C . At what temperature does benzene boil when the external pressure is 410 ? This is how I am solving this problem,
ln(415/760)= (30720/8.314)*(1/80.1 - 1/T2)

It is asking to answer using two significant figures and it keeps telling me I'm incorrect. Any help would be appreciated.

Thanks.

  • chemistry -

    ops I meant to put 410 in the equation.

  • chemistry -

    Did you and I work on this problem yesterday. If not, then let me tell you quickly where your problem(s) is/are. First you MUST use Kelvin for T1. That is 80.1 + 273.16. I think the problem asks for T in C BUT you must solve the problem first, using Kelvin, then convert back to C. Second, I see you typed the problem as 410 but substituted 415. Take care that you are solving the problem with the right numbers.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question