math
posted by strawberryfields .
okay, this i cannot figure out anywhere.
2[ln(x)ln(x+1)ln(x1)]
evaluate into logarithm of a single quantity.

ln[x/(x^21)^2]

would you mind telling me how you got it?
i don't get this problem..
thanks forthe answer though! 
Actually I should have written it as
ln{[x/(x^21]^2}
The ln(x+1)ln(x1) in the denominator is ln {1/[(x+1)(x1)] = ln [1/(x^21)]
Adding ln x puts the x in the numerator of [x/(x^21)]
The two in front of
2[ln(x)ln(x+1)ln(x1)]
is the same as taking the log of the square of [ln(x)ln(x+1)ln(x1)]
Respond to this Question
Similar Questions

math
write the expression as the logarithm of a single quantity. 2 In 8 + 5 In z My answer is 7 In 8z but I don't not think this is right! 
Calculus
express the given quantity as a single logarithm: ln(a+b)+ln(ab)8ln(c) 
Calculus
Write the logarithm of a single quantity: 2ln(x)+ln(4)(1/2)ln(9) 
Cal
Express the given quantity in a single logarithm. ln(a + b) + ln(a  b)  2 ln c 
math
Write the expression as a logarithm of a single quantity. (4marks) A)3log5a + 4log5b  2log5c B)3log2 1/3log(x^21) 
Calculus
Write as a single logarithm of a single quantity ln(3)+1/2ln(x+2)4ln(1+sqrtx) 
math
How would you condense a logarithm expression into a single quantity if the logs have different bases? 
Calculus
Write the expression as the logarithm of a single quantity. ln 2 + 1/2 ln(x +1)2 ln(1+ x^(1/2)) 
Math
Condense the expression to the logarithm of a single quantity. 5lnx6ln(x+2) 
math condense logs
write the expression as the logarithm of a single quantity 3[ln x2 ln(x^2+1)]+2 ln 5