x = 3 - y^2
y = x - 3
Find the points of intersection.
If someone could even get me to the point where it gets written in general form (both equations set to 0..) I would be forever grateful.
sub the second equation into the first, so
x = 3 - (x-3)^2
x = 3 - (x^2 - 6x + 9)
x^2 - 5x + 6 = 0
(x-2)(x-3) = 0
x = 2 or x = 3
if x = 2, then y = 2-3 = -1
if x = 3, then y = 3-3 = 0
so they intersect at (2,-1) and (3,0)