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x = 3 - y^2
y = x - 3

Find the points of intersection.

If someone could even get me to the point where it gets written in general form (both equations set to 0..) I would be forever grateful.

  • math -

    sub the second equation into the first, so

    x = 3 - (x-3)^2
    x = 3 - (x^2 - 6x + 9)
    x^2 - 5x + 6 = 0
    (x-2)(x-3) = 0
    x = 2 or x = 3

    if x = 2, then y = 2-3 = -1
    if x = 3, then y = 3-3 = 0

    so they intersect at (2,-1) and (3,0)

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