Precalculus
posted by Mary .
Find the quotient
3[cos5pi/12+isin5pi/12] divided by 6[cospi/12+isinpi/12]. Express the quotient in rectangular form.
I worked it out as:
1/2[cospi/3+isinpi/3]
=1/2(1/2+1/2i)
=1/2+1/2i
Is this right?

You started out OK but went astray somewhere.
Here's one way to do it.
Rewrite it as
(1/2)e^(i*5 pi/12)/e^(i*pi/12)
= (1/2)e^(i*pi/3)
= (1/2)[cos (pi/3)+ i sin(pi/3)]
You got that far..
= (1/2)[(1/2) + i(sqrt3)/2]
1/4 + i (1/4)* sqrt3 
Ok thanks i know where i went wrong
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