solve the system 3x+4y=40 y-2y=0
To solve the system of equations:
1) 3x + 4y = 40
2) y - 2y = 0
Let's simplify Equation 2 by combining the y terms:
2) -y = 0
Since -y = 0, we know that y = 0. Now, we can substitute this value of y in Equation 1 to solve for x:
3x + 4y = 40
Substitute y = 0:
3x + 4(0) = 40
3x + 0 = 40
3x = 40
Divide both sides by 3 to solve for x:
3x/3 = 40/3
x = 40/3
Therefore, the solution to the system of equations is x = 40/3 and y = 0.