In 1990 th elife expectancy of males in a certain country was 62.6 years. In 1996 it was 65.9 years. Let E represent the life expectancy in a year t and let t represent the number of years since 1990. The linear function E(t) that fits the data is E(t) = t +

use the function to predict life expectancy of males in 2006

It will be of the form E = 62.6 + C*t

where C is a constant. Use the fact that E = 65.9 when t = 6 to evaluate the constant.

Then plug t = 16 into your formula to get the life expectancy in 2006, assuming the linear relationship remains valid.

I hope that you understand these directions and can finish the problem yourself.

To use the linear function E(t) = t + b to predict the life expectancy of males in 2006, we first need to find the value of b, which represents the initial life expectancy in 1990.

Given that the life expectancy in 1990 was 62.6 years, we can substitute the initial year t = 0 and life expectancy E(t) = 62.6 into the linear function:

62.6 = 0 + b

Simplifying the equation, we find that b = 62.6.

Now, we have the function E(t) = t + 62.6. To predict the life expectancy in 2006, we substitute t = 2006 - 1990 = 16 into the function:

E(16) = 16 + 62.6

Calculating the expression, we find that E(16) = 78.6.

Therefore, the predicted life expectancy of males in 2006 is 78.6 years.