The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1. Cs(s)-Cs(g)
2. 1/2 Cl2(g)-Cl(g)
3. Cs(g) –Cs^+(g) + e^-
4. Cl(g) + e^- - Cl^-(g)
5. Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
See my response to iuyter just a few posts above.
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The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1.Cs(s)-Cs(g)
2.1/2 Cl2(g)-Cl(g)
3.Cs(g) –Cs^+(g) + e^-
4.Cl(g) + e^- - Cl^-(g)
5.Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
To determine which steps absorb or release energy in the formation of CsCl from Cs(s) and Cl2(g), we need to analyze the changes in enthalpy (ΔH) for each step.
Step 1: Cs(s) → Cs(g)
This step involves the conversion of a solid (Cs(s)) to a gas (Cs(g)). The sublimation process typically requires energy input, so this step absorbs energy.
Step 2: 1/2 Cl2(g) → Cl(g)
In this step, half of the Cl2 gas molecules convert into Cl gas molecules. The dissociation of Cl2 requires energy input, so this step absorbs energy.
Step 3: Cs(g) → Cs+(g) + e^-
This step involves the ionization of Cs gas, where Cs atoms lose an electron to form Cs+ ions. Ionization typically requires energy input, so this step absorbs energy.
Step 4: Cl(g) + e^- → Cl^-(g)
In this step, Cl gas gains an electron to form Cl- ions. The process of electron gain typically releases energy, so this step releases energy.
Step 5: Cs+(g) + Cl^-(g) → CsCl(s)
The final step involves the formation of solid CsCl from Cs+ and Cl- ions. The formation of an ionic solid usually releases energy, so this step releases energy.
In summary:
- Steps 1, 2, and 3 absorb energy.
- Steps 4 and 5 release energy.