how do i figure out the percentage error , as well as the absolute error of
a) (10.00+/- .02)mL x .42 mol/L
b) (10.00 +/- .02)mL + (10.00 +/- .02)mL
http://science.widener.edu/svb/stats/error.html
On the first, percent error is .02/10 x 100
absolute error is .02
On the last, you have to do some math. See the link
error=sqrt (.02^2+ .02^2)=.028
then, use the formulas above.