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A 3.00x10^-3kg lead bullet travels at a speed of 2.40x10^2m/s and hits a wooden post. if half the heat energy generated remains with the bullet, what is the increase in temperature of the embedded bullet?(ci=1.28x10^2 j/kg degrees C

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    Compute the kinetic energy of the bullet. Take half of that value as heat added to the bullet, Q.

    Q = (1/2) M V^2

    From that Q and the specific heat C and mass, compute the temperature rise, delta T.

    delta T = Q /(M C) = (1/2) V^2/C

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    225

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    112.5, BIATCHES

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