Find the equation of the line
With a slope of 3 that goes through the point (-5, -1)
y=mx+b
you are given m=3
y=3x+b Put in the point . solve for b.
Then the equation of the line is
y=mx+b
could you show me how to do that please?
To find the equation of a line with a given slope that passes through a given point, we can use the point-slope form of a linear equation. The point-slope form is given by:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope.
In this case, the slope (m) is 3, and the given point is (-5, -1). Substituting these values into the point-slope form, we get:
y - (-1) = 3(x - (-5))
Simplifying:
y + 1 = 3(x + 5)
Expanding the brackets:
y + 1 = 3x + 15
Finally, rearranging the equation to the standard form (Ax + By = C):
3x - y = 14
Therefore, the equation of the line with a slope of 3 that passes through the point (-5, -1) is 3x - y = 14.