# algebra II

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Find the equation of the line

With a slope of (-1/3) that goes through the point (2, -4)

With a slope of 3 that goes through the point (-5, -1)

• algebra II -

y=mx+b

(x,y)

You multiply x by m, the slope.
You get to y by adding b.

(2,-4)

You multiply 2 (x) by -1/3 (m), the slope.
You get to -4 (y) by adding -3.33 (b) = -10/3

Therefore, y=(-1/3)x-(10/3)

The next one is done the same way.

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