algebra II
posted by kate .
Find the equation of the line
With a slope of (1/3) that goes through the point (2, 4)
With a slope of 3 that goes through the point (5, 1)

y=mx+b
(x,y)
You multiply x by m, the slope.
You get to y by adding b.
(2,4)
You multiply 2 (x) by 1/3 (m), the slope.
You get to 4 (y) by adding 3.33 (b) = 10/3
Therefore, y=(1/3)x(10/3)
The next one is done the same way.