Algebra
posted by Kim .
The base of a triangle is 8cm greater than the height. The area is 42cm^2. Find the height and length of the base.

Area of triangle = 1/2(height x base)
The problem states that base is 8 cm greater than the height; therefore, base8 = height.
A = 1/2(b*h)
42 = 1/2(b*[b8])
84=(b^28b)
rearrange to
b^2  8b 84
factor to
(b+8)(b14)
Therefore, b = 8 cm which makes no sense and
b = +14 cm
and height = 148 = 6
Check:
1/2(b*h) = area
1/2(14*6) = 1/2(84)=42
Check my work.