which ordered pair is not in the solution set of y>2x+1?

1: (1,4)
2: (3,8)
3: (1,6)
4: (2,5)

whats the answer ?

plz help me ...its urgent

To determine which ordered pair is not in the solution set of y > 2x + 1, we need to test each pair by substituting the x and y-values into the inequality and see if it holds true.

Let's go through each option one by one and verify if the inequality is satisfied:

1. (1,4): Substitute x = 1 and y = 4 into the inequality: 4 > 2(1) + 1. This equation simplifies to 4 > 3, which is true.
Therefore, (1,4) is in the solution set.

2. (3,8): Substitute x = 3 and y = 8 into the inequality: 8 > 2(3) + 1. This equation simplifies to 8 > 7, which is true.
Thus, (3,8) is in the solution set.

3. (1,6): Substitute x = 1 and y = 6 into the inequality: 6 > 2(1) + 1. This equation simplifies to 6 > 3, which is true.
Hence, (1,6) is in the solution set.

4. (2,5): Substitute x = 2 and y = 5 into the inequality: 5 > 2(2) + 1. This equation simplifies to 5 > 5, which is false.
Therefore, (2,5) is not in the solution set.

So, the ordered pair not in the solution set of y > 2x + 1 is (2,5).

Just plug in the values of the ordered pair to see which one is false.

For 1) 4>(2*1 + 1) --- true
for 2) 8>(2*3 + 1) --- true

continue for 3 and 4 and you will have your answer