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math help me

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an ellipse has an area of 4.17 in^2, and a minor axis that is 2 inch long. solve fot the major axis.

how do i solve this?

  • math help me -

    for any ellipse of the form
    x^2/a^2 + y^2/b^2 = 1
    the area of the ellipse is (ab)pi

    so if the minor axis is 2 inches, then b=1
    abpi = 4.17
    api = 4.17
    a = 4.17/pi = 1.32735
    so the major axis or 2a is 2.6547 units long.

    check with this:

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