math help me
posted by Anonymous .
an ellipse has an area of 4.17 in^2, and a minor axis that is 2 inch long. solve fot the major axis.
how do i solve this?

for any ellipse of the form
x^2/a^2 + y^2/b^2 = 1
the area of the ellipse is (ab)pi
so if the minor axis is 2 inches, then b=1
abpi = 4.17
api = 4.17
a = 4.17/pi = 1.32735
so the major axis or 2a is 2.6547 units long.
check with this:
http://www.csgnetwork.com/areaellipse.html