A train left Podunk and traveled north at 75km/h. Two hours later, another train left Podunk and traveled in the same direction at 100 km/h. How many hours had the first train travelee when the second overtook it?
The distance between the trains when the second one startes is 150 km. The ditance between trains dimishes at a rate of 25 km/h.
Divide 150km by 25km/h for the answer.
6 hours
To find out how many hours the first train had traveled when the second train overtook it, we need to determine the time it took for the second train to catch up to the first train.
Let's assume that the first train traveled for 't' hours when the second train caught up to it.
Since the second train left two hours later, it traveled for 't - 2' hours when it caught up to the first train.
Now, let's find the distance traveled by each train:
Distance traveled by the first train = Speed of the first train * Time = 75 km/h * t
Distance traveled by the second train = Speed of the second train * Time = 100 km/h * (t - 2)
When the second train catches up to the first train, both trains would have traveled the same distance. So, we can equate the distances:
75t = 100(t - 2)
Simplifying this equation:
75t = 100t - 200
25t = 200
t = 8
Therefore, the first train had traveled for 8 hours when the second train overtook it.