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Let f be the function given by
f(x)=2ln(x^2+3)-x with domain -3 is less than or equal to x which is less than or equal to 5
a) Find the x-coordinate of each relative maximum point and each relative minimum point of f. Justify your answer.
b) Find the x-coordinate of each inflection point of f.
c) Find the absolute maximum value of

  • Calc -

    f'(x) = 2(2x)/(x^2 + 1) - 1
    = 0 for max/min

    for this I got x = 2 ± √5
    These lie within your domain so

    You will have to find
    f(-3), f(2+√5)), f(2-√5) and f(5) to see which is the maximum

    for f''(x) I got (4(x^2 + 1) - 4x(2x))/(x^2 + 2)^2

    setting this equal to zero, I got x = ± √2

    sub back in the original to find the two inflection points.

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