jose and sara are walking around the track at the same time. jose walks one lap every 8 min. sara walks a lap 6 min.what is the least amount of time they would both have to walk for them to cross the starting point together
24 min.
answer=24 mins
8x3=24
6x4=24
that is the least amount of time.
Just find the greatest common factor.
I believe you can solve this problem by finding the LCM (least common multiple) of 6 and 8, which is 24. So it will take 24 minutes before Jose and Sara will cross the starting point together.
what is the lcm of 6,8
what is the lcm of 15,25
To find the least amount of time they would both have to walk for them to cross the starting point together, we need to find the least common multiple (LCM) of their times.
The LCM of 8 and 6 can be found by listing their multiples and finding the smallest common multiple:
Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, ...
Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, ...
From the lists above, we can see that 24 is the smallest number that appears in both lists and is the LCM of 8 and 6.
Therefore, the least amount of time they would both have to walk for them to cross the starting point together is 24 minutes.